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Question

In the given circuit, find charge across the capacitor C, when steady state is reached.
1176892_4857f98723de45a29b381d3d73985f17.JPG

A
6μC
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B
9μC
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C
18μC
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D
None of these
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Solution

The correct option is C 18μC
R.E.F image
Capacitor circuit
When steady state is reached capacitor will
behave as open circuit Diagram is shown
i=12+63
i=6A
voltage across capacitor =(vc)
ve=(18+9)v
vc=9v
|vc|=9v
Charge a cross capacitor c
q=cv
q=2μF×qv
q=18μc

1060704_1176892_ans_b2a2166882b446f0ba8f4ffa7a61723d.png

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