Question

In the given circuit for ideal diode, the current through the battery is:

• A. 0.5 A
• B. 1.5 A
• C. 1 A
• D. 2 A

Answer 1

The correct option is C 1 A


Voltage = 10 V
Diode is forward biased
$R_{eq}=5\Omega =5\Omega =10\Omega$
$I=\frac{10}{10}=1A$