In the given circuit, it is observed that the current I is independent of the value of the resistance $R_{6} .$ Then the resistance values must satisfy

(IIT-JEE 2001)

$R_{1} R_{2} R_{5} = R_{3} R_{4} R_{6}$

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$\frac{1}{R_{5}} + \frac{1}{R_{6}} = \frac{1}{R_{1} + R_{2}} + \frac{1}{R_{3} + R_{4}}$

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$R_{1} R_{4} = R_{2} R_{3}$

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$R_{1} R_{3} = R_{2} R_{4} = R_{5} R_{6}$

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Solution

The correct option is C
$R_{1} R_{4} = R_{2} R_{3}$

$R_{1}, R_{2}, R_{3}, R_{4}$ are in a wheatstone arrangement.
$∴ R_{6}$ would not matter if $\frac{R_{1}}{R_{3}} = \frac{R_{2}}{R_{4}}$

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In the given circuit, it is observed that the current I is independent of the value of the resistance R6. Then the resistance values must satisfy (IIT-JEE 2001)

The correct option is C R1R4=R2R3 R1,R2,R3,R4 are in a wheatstone arrangement. ∴R6 would not matter if R1R3=R2R4

In the given circuit, it is observed that the current I is independent of the value of the resistance $R_{6} .$ Then the resistance values must satisfy

(IIT-JEE 2001)

The correct option is C
$R_{1} R_{4} = R_{2} R_{3}$

$R_{1}, R_{2}, R_{3}, R_{4}$ are in a wheatstone arrangement.
$∴ R_{6}$ would not matter if $\frac{R_{1}}{R_{3}} = \frac{R_{2}}{R_{4}}$