Question

In the given circuit, potential difference across the capacitor in steady state is

• A. $\frac{3}{4}$ V
• B. $\frac{1}{2}$ V
• C. $\frac{4}{3}$ V
• D. $\frac{5}{4}$ V

Answer 1

The correct option is C $\frac{4}{3}$ V

During steady state no current flows through the capacitor containing arm, so the potential across the capacitor will be same as the potential across arm $AB$. By applying K.V.L in the lower circuit we will get
$8V-2V=2ii=3A$
Now apply K.V.L in the left circuit of AB, we will get
$-2\left(i-i_1\right)-4\left(i-i_1\right)+2=0\therefore i_1=\frac{8}{3}$
Voltage across arm AB will be $4\left(i-i_1\right)=\frac{4}{3}V$