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B
3.82 V
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C
2.5 V
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D
4 V
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Solution
The correct option is B 3.82 V Here we assume that potential of point A is higher than 2 V. 8−2=2(i1+i2)+4i2 6=2i1+6i2⇒3=i1+3i2 ....(1) 8+6=2(i1+i2)+6i1
14=8i1+2i2⇒7=4i1+i2 ....(2) By (1) & (2) i2=511 VA−2=4×511⇒VA=2+2011=4211=3.82V