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Byju's Answer
Standard XIII
Physics
Kirchoff's Voltage Law
In the given ...
Question
In the given circuit potential of junction
P
is :
A
4 V
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B
0 V
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C
3.2 V
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D
2.8 V
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Solution
The correct option is
C
3.2 V
Let the voltage of point
P
be
V
P
and currents are flowing in the circuit as shown in the figure.
Here we assume that potential of point
P
is higher than
2
V
.
Now applying KVL between points of potential
12
V
and
2
V
:
12
−
4
i
−
2
i
1
=
2
2
i
+
i
1
=
5
------
(
1
)
Applying KVL between points of potential
12
V
and
0
V
:
12
−
4
i
−
2
(
i
−
i
1
)
=
0
3
i
−
i
1
=
6
------
(
2
)
From
(
1
)
and
(
2
)
we have,
i
=
11
5
A
So, potential at point
P
,
V
P
=
12
−
4
i
=
12
−
4
×
11
5
=
3.2
V
Suggest Corrections
0
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