Question

In the given circuit potential of junction P is

• A. 4 V
• B. 0 V
• C. 3.2 V
• D. 2.8 V

Answer 1

The correct option is C 3.2 V


Applying KCL:
$12=4i+2(i-i_1)$
$6=3i-i_1$ .....(1)

$10=4i+2i_1$
$5=2i+i_1$.....(2)
By solving (1) and (2), we get $i=\frac{11}{5}A$
So, potential at point P,$V_P=12-4i=12-4\times \frac{11}{5}=3.2V$