In the given circuit, separation between plates of capacitor is doubled very slowly, keeping battery connected. While increasing seperation between plates, .
A
Work done by battery will be positive
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B
Heat will be generated in resistance
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C
Work done by battery will be negative.
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D
Work done by electrostatic force will be positive
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Solution
The correct options are C Work done by battery will be negative. D Work done by electrostatic force will be positive For discharging of the capacitor, work done by battery would be negative. Since, the capacitor is moved very slowly, every transient state can be approximated as steady state, resulting in very minimal current flow and no heat generation.