Question

In the given circuit, the \(AC\) source has \(\omega = 100\) rad/s. Considering the inductor and capacitor to be ideal, the correct choice(s) is(are)


\( 0^{20 v} \)

• A. The voltage across $100\Omega$ resistor = $10\sqrt{2}V$
• B. The current through the circuit, $I$ is $0.3A$
• C. The current through the circuit, $I$ is $0.3\sqrt{2}A$
• D. The voltage across $50\Omega$ resistor = $10V$

Answer 1

Answer: (A), (B)

The current through the circuit, $I$ is $0.3A$

$X_C=100\Omega$

$X_L=50\Omega$

$I_1=\frac{20}{100\sqrt{2}}$

$I_2=\frac{20}{50\sqrt{2}}$

$I=\sqrt{I_1^2+I_2^2}=\frac{1}{\sqrt{10}}\approx 0.3A$

$V^2+V^2=(20{)}^2$

$\Rightarrow 2V^2={20}^2$

$\Rightarrow V=\frac{20}{\sqrt{2}}$

$\Rightarrow V=10\sqrt{2}$