The correct option is A 100Ω
Let, i is the current flowing through the circuit. In the given circuit the ammeter reading is zero.
Hence, the voltage drop across 500Ω resistance is 10V (as the batteries are oppositely connected).
The current through 500Ω resistance is,
i=10500
i=150A
Hence by Ohm's law for resistance R, we can write
R×150=2
∴R=100Ω