Question

In the given circuit the charge passing through the battery is $48\mu C$. The potential difference of capacitor $C$ is

• A. $6\text{V}$
• B. $8\text{V}$
• C. $3\text{V}$
• D. $4.5\text{V}$

Answer 1

The correct option is A $6\text{V}$

Using point potential method, the circuit can be redrawn as


Since, $q=C_{eq}V$

$\Rightarrow 48=\frac{8\times (C+4)}{8+4+C}\times 12$

$\Rightarrow C=4$
As $C$ and $4\mu F$ capacitor are in parallel,
Potential across C is $V=\frac{Q}{C+4}=\frac{48}{8}=6V$

Hence, the correct answer is (A).