Question

In the given circuit, the current through the $5\text{mH}$ inductor, in steady state, will be -

• A. $\frac{5}{3}\text{A}$
• B. $\frac{7}{3}\text{A}$
• C. $\frac{4}{3}\text{A}$
• D. $\frac{8}{3}\text{A}$

Answer 1

The correct option is D $\frac{8}{3}\text{A}$

In steady state, current from the battery into the circuit is,

$i_0=\frac{E}{R}=\frac{20}{5}=4\text{A}$


Now, the current through $5\text{mH}$ inductor is,

$i_1=\frac{L_2}{L_1+L_2}\times i_0$

$=\frac{10}{5+10}\times 4$

$=\frac{8}{3}\text{A}$

Hence, option $\left(D\right)$ is the correct answer.