Question

In the given circuit, the potential difference across $3\mu F$ capacitor will be:

• A. $12V$
• B. $10V$
• C. $6V$
• D. $4V$

Answer 1

Answer: (B)

$10V$

both capacitor and battery are in series so

$V_{eq}=20-4=16v$

$C_{e}q=\frac{3\times 5}{5+3}=\frac{15}{8}$

$q=C_{eq}\times V_{eq}=\frac{15}{8}\times 16=30$

$V_3=\frac{q}{c}=\frac{30}{3}=10v$