Question

In the given circuit the steady state current through the $2\Omega$ resistor is

• A. $0.6\text{A}$
• B. $0.9\text{A}$
• C. $1.2\text{A}$
• D. $1.5\text{A}$

Answer 1

The correct option is B $0.9\text{A}$

Since capacitor is a D.C. blocking element, so no current flows through the branch containing the capacitor in steady state. However, a voltage drop will exist across this branch.
$R_{net}=4\Omega$
$\Rightarrow I_{total}=\frac{V}{R_{net}}=\frac{6\text{V}}{4\Omega }=1.5\text{A}$
Voltage drop across $2.8\Omega$ is $V_1=(2.8\times 1.5)$
$\Rightarrow V_1=4.2\text{V}$
So, potential across parallel combination of $2\Omega$ and $3\Omega$ is
$V_2=6-4.2=1.8\text{V}$
If $I_2$ is the current in $2\Omega$ resistor, then
$I_2=\frac{1.8}{2}=0.9\text{A}$
Hence, the correct answer is (B).