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Question

In the given circuit, the value of current in different branches and one resistor are shown. The potential at point B with respect to the point A is


A
+1 V
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B
2 V
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C
1 V
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D
+2 V
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Solution

The correct option is A +1 V

Using Kirchhoff's junction at C, we get

i1+i3=i2
1 A+i3=2 Ai3=1 A

Potential at point B with respect to the point A is

VA+1+i3(2)2=VB
VA+1+1×(2)2=VB
VBVA=+1 V

Hence, option (d) is correct.

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