Question

In the given $\Delta ABC$, $AZ=ZC;BM=MC$ and if area of $\Delta ABC=8m^2$, find the area of $\Delta BZM$.

• A. $1.56$ $m^2$
• B. $2$ $m^2$
• C. $1.67$ $m^2$
• D. $1.65$ $m^2$

Answer 1

The correct option is B $2$ $m^2$

AS '$Z$' is mid point

$\Rightarrow ar\left(ABZ\right)=ar\left(BZC\right)$

$\Rightarrow ar\left(BZC\right)=\frac{1}{2}ar\left(ABC\right)$

'$M$' is midpoint $\Rightarrow ar\left(BZM\right)=ar\left(ZMC\right)$

$ar\left(ZMB\right)=\frac{1}{2}ar\left(BZC\right)=\frac{1}{2}ar\left(ABC\right)$

$\Rightarrow ar\left(BZM\right)=2m^2$