Question

In the given diagram, PO is the incident ray, OQ is the reflected ray and ON is the normal to the reflecting surface. Find the angle x.

• A. ${45}^{\circ }$
• B. ${90}^{\circ }$
• C. ${60}^{\circ }$
• D. ${30}^{\circ }$

Answer 1

The correct option is C ${60}^{\circ }$

Given:
$\angle POM={30}^{\circ }$
Angle of reflection is $x$

Now, ON is normal to the reflecting surface.
$\angle MON={90}^{\circ }$
$\angle MOP+\angle PON={90}^{\circ }$
${30}^{\circ }+\angle PON={90}^{\circ }$
$\angle PON={60}^{\circ }$

According to the law of reflection, angle of incidence is equal to the angle of reflection.
$\angle PON=x$
$x={60}^{\circ }$