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Question

In the given diagram, the container contains vinegar solution and graphite rods are dipped which acts as electrodes. These rods are connected to a battery and bulb with wires. The circuit is closed. What is the observation?

A
Blub glows brightly
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B
Blub glows dimly
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C
Blub will not glow
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D
Blub glowsfor a second
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Solution

The correct option is B Blub glows dimly
If the electrolyte is strong, the blub will glow brightly and if it is weak, then it will glow with dim light. Vinegar is chemically called acetic acid, and is a weak electrolyte (these substances partially dissociate into ions and the solution contains both ions and molecules). So, the blub will glow with dim light.

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