Question

In the given diagram , $△$ PQO is congruent to which triangle ?

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Answer 1

We know that $\angle$OQP = $\angle$ORP = ${90}^{\circ }$. (tangent makes ${90}^{\circ }$ with the radius at point of contact).

Also OQ = OR = radius

PO = PO (common side)

Therefore $△$PQO ic ongruent to $△$PRO by RHS congruency. (order PRO is important).