Question

In the given electric circuit, calculate:
(i) the value of resistance $R$.
(ii) potential difference between $A$ and $B$.

Answer 1

I )

The value of current through the branch is 1.5 A and the voltage across R is 1 Volt , so the value of Resistance is,

$V=IR$

So putting the value of V and I is,

$R=\frac{V}{I}$

$R=\frac{1}{1.5}\Omega$

$R=\frac{2}{3}\Omega$

II )

Now, Applying Kirchhoff's Voltage law in the branch,

$V_A-(1.5\times 2)-(\frac{2}{3}\times 1.5)-(4\times 1.5)=V_B$

$V_A-V_B=10$ V