In the given electron dot structure of molecule ABC, the atomic number of A and C is 1 (consider both of them as hydrogen atom). The no. of valence elctrons in B are _____.

six

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five

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eight

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four

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Solution

The correct option is A six
In a Lewis dot structure, the nucleus and the inner shell electrons are represented using the symbol of the element. While, valence electrons are represented as dots around the symbol.

In the given compound, the number of electrons around B in the structure is eight. B share two electrons to form a covalent bond. While, four electrons remain unshared.

Since two electrons are shared, the number of valence electrons of B = 8-2 = 6.

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