In the given electron dot structure of molecule ABC, the atomic number of A and C is 1 (consider both of them as hydrogen atom). The no. of valence elctrons in B are _____.

six

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five

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eight

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four

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Solution

The correct option is A six
In a Lewis dot structure, the nucleus and the inner shell electrons are represented using the symbol of the element. While, valence electrons are represented as dots around the symbol.

In the given compound, the number of electrons around B in the structure is eight. B share two electrons to form a covalent bond. While, four electrons remain unshared.

Since two electrons are shared, the number of valence electrons of B = 8-2 = 6.

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In the given electron dot structure of molecule ABC, the atomic number of A and C is 1 (consider both of them as hydrogen atom). The no. of valence elctrons in B are _____.

Question 41
In electron dot structure, the valence shell electrons are represented by crosses or dots
(a) The atomic number is 17. Write its electronic configuration.
(b) Draw the electron dot structure of chlorine molecule.

Q. A _________ dot structure of an element is surrounded by the valence electrons of its atoms represented in the form of dots.

Q. A Lewis dot structure of an element is surrounded by the valence electrons of its atoms represented in the form of dots.

Q. The necessary steps required to shown the formation of

C C l

_{4}

by Lewis electron dot diagram have been jumbled. Arrange them in a sequence :
(a) This is how an electron pair is shared between

C

and

C l

. This is the Lewis electron dot diagram for

C C l_{4}

.
(b) Write the symbol of chlorine and represent its valence electrons with the help of crosses.
(c) Write the symbol of carbon and represent its valence electrons with the help of dots.
(d) When carbon combines with four chlorine atoms, the carbon atom contributes four electrons for sharing whereas each chlorine atom contributes only one electron for sharing. Thus, both the atoms in

C C l

_{4}

attain an octet.

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