In the given equation a- 2 3 b-5If a-1- find value of b-

The correct option is A 6 Put a=1 in eq #160;1= 2 3 b+5 #160;=1 5= 2 3 b = 4× 3 2 =b,b= 6 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VI

Mathematics

Solution of an Equation

In the given ...

Question

In the given equation
$a = \frac{2}{3} b + 5$
If $a = 1$ , find value of $b$ .

- 6

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $- 6$
Put $a = 1$ in eq
$1 = \frac{2}{3} b + 5$
$= 1 - 5 = \frac{2}{3} b$
$= \frac{- 4 \times 3}{2} = b, b = - 6$

Suggest Corrections

Similar questions

Find the value of $x$ in the equation
$\frac{x}{3} + 4 = 2$

Q. Find the value of the expression a - 3b, if a = 4 and b = 6.

$If \frac{3 x + 5}{4} + 1 = \frac{x + 3}{6}, then find the value of x .$

Q. If

A = [\begin{matrix} 2 & 5 4 & 4 \end{matrix}], B = [\begin{matrix} 0 & 5 1 & 6 \end{matrix}]

, find

5 A^{'} + 3 B^{'}

If difference of reciprocal of roots of a quadratic equation $a x^{2} + b x + c = 0$ is $\frac{1}{4}$ , and difference of roots is 2. Then the value of c in the given equation is

Join BYJU'S Learning Program

In the given equationa=23b+5If a=1, find value of b.

The correct option is A −6Put a=1 in eq1=23b+5=1−5=23b=−4×32=b,b=−6

In the given equation
$a = \frac{2}{3} b + 5$
If $a = 1$ , find value of $b$ .

The correct option is A $- 6$
Put $a = 1$ in eq
$1 = \frac{2}{3} b + 5$
$= 1 - 5 = \frac{2}{3} b$
$= \frac{- 4 \times 3}{2} = b, b = - 6$