In the given fig, find the perimeter of ΔABC, if AP = 10 cm
∵BC touches the circle at R
∵Tangents drawn from external point to the circle are equal
∴AP = AQ, BR = BP & CR = CQ
∴Perimeter of ΔABC = AB +BC +AC
= AB + BR +RC + AC
= AB + (BP + CQ) + AC
= (AB + BP) + (CQ + AC)
= AP + AQ
= 2AP
= 2(10)
= 20cm