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Question

In the given fig, find the perimeter of ΔABC, if AP = 10 cm

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Solution

BC touches the circle at R

Tangents drawn from external point to the circle are equal

AP = AQ, BR = BP & CR = CQ

Perimeter of ΔABC = AB +BC +AC

= AB + BR +RC + AC

= AB + (BP + CQ) + AC

= (AB + BP) + (CQ + AC)

= AP + AQ

= 2AP

= 2(10)

= 20cm


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