In the given fig. if AD = BC and AD || BC, then:

AB = AD

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AB = DC

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BC = CD

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None

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Solution

The correct option is D AB = DC
In the give fig. AD = BC, AC = AC,
$∠ A D C = ∠ A B C$ ( $∵$ AD || BC)
By SAS theorem $Δ A B C ≅ Δ C D A$
So AB = DC.

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