In the given fig., locate the position where the ball lies on the number line.

$\frac{1}{5}$

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$\frac{2}{5}$

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$\frac{3}{5}$

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$\frac{4}{5}$

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Solution

The correct option is C
$\frac{3}{5}$

The space between 0 and 1 is divided into 10 equal parts. The ball lies in the sixth place.

Therefore, the location ball lies in is, $\frac{6}{10} = \frac{3}{5}$

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Similar questions

In the given figure, locate the position where the ball lies on the number line.

1^{2} - \frac{2^{2}}{5} + \frac{3^{2}}{5^{2}} - \frac{4^{2}}{5^{3}} + \frac{5^{2}}{5^{4}} - \frac{6^{2}}{5^{5}} + . . . . .

1^{2} - \frac{2^{2}}{5} + \frac{3^{2}}{5^{2}} - \frac{4^{2}}{5^{3}} + \frac{5^{2}}{5^{4}} - \frac{6^{2}}{5^{5}} + . . . .

\frac{25}{k} = 1^{2} - \frac{2^{2}}{5} + \frac{3^{2}}{5^{2}} - \frac{4^{2}}{5^{3}} + \frac{5^{2}}{5^{4}} - \frac{6^{2}}{5^{2}} + . . . . . . \infty

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