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Question

In the given fig, PQ is tangent at a point R of the circle with centre O. If TRQ=30, find PRS.


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    Solution

    Here,

    TRQ=30
    PRS = ?
    ∠SRT = 90 because ST is the diameter.
    so,
    ∠TRQ + ∠SRT + ∠PRS = 180
    30 + 90 + ∠PRS = 180
    ∠PRS = 180 -120 = 60


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