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Question

In the given figure, A(0, 2y) and B(2x, 0) are the end-points of line segment AB. The coordinates of point C, which is equidistant from the three vertices of ∆AOB, are


(a) (x , y)
(b) (y , x)
(c) x2,y2
(d) y2,x2

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Solution

(a) (x , y)
The midpoint of AB is equidistant from the three vertices of ∆AOB.
Therefore,
Midpoint of AB=0+2x2,2y+02 A0,2y and B2x,0⇒x1=0, y1=2y and x2=2x, y2=0i.e. x, y
Hence, the coordinates of C are (x, y).

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