In the given figure, a=15 m/s2 represents the total acceleration of a particle moving in the clockwise direction in a circle of radius R=2.5m at a given instant of time. The speed of the particle is:
A
6.2m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
4.5m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
5.0m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5.7m/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D5.7m/s
Step 1: Centripetal acceleration [Ref. Fig.]
Total acceleration has two components, i.e. tangential acceleration (at) and centripetal acceleration (ac)
From the figure ac=acos30∘....(1)
Step 2: Speed calculation
Centripetal acceleration is given by
ac=v2R....(2)
where v is the speed of the particle.
From equation (1) and (2)
acos30o=v2R
⇒15cos30o=v22.5
⇒v=√32.5m/s=5.7m/s
Hence speed of the particle is 5.7m/s. Option D is correct