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Question

In the given figure, a=15 m/s2 represents the total acceleration of a particle moving in the clockwise direction in a circle of radius R=2.5m at a given instant of time. The speed of the particle is:

516343_67958f7fd4044428a73faeb3e2237e36.png

A
6.2m/s
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B
4.5m/s
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C
5.0m/s
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D
5.7m/s
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Solution

The correct option is D 5.7m/s
Step 1: Centripetal acceleration [Ref. Fig.]
Total acceleration has two components, i.e. tangential acceleration (at) and centripetal acceleration (ac)
From the figure ac=acos30 ....(1)

Step 2: Speed calculation
Centripetal acceleration is given by
ac=v2R ....(2)
where v is the speed of the particle.
From equation (1) and (2)
acos30o=v2R
15cos30o=v22.5
v=32.5m/s=5.7m/s

Hence speed of the particle is 5.7m/s. Option D is correct

2110419_516343_ans_737676cc44724b818ace831440d134ef.png

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