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B
45°
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C
90°
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D
30°
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Solution
The correct option is B45° Itcanbeobservedthat∠AOC=∠AOB+∠BOC=60°+30°=90°Weknowthatanglesubtendedbyanarcatthecentreisdoubletheanglesubtendedbyitanypointontheremainingpartofthecircle.∠ADC=12∠AOC=12×90°=45°