In the given figure, A,B,C are the mid-points of sides xy, yz and xz respectively of △xyz.
If AB= 5.5 cm, BC= 3.5 cm and AC= 6 cm, then perimeter of △xyz=
30
Using mid-point theorem we have,
BC=12YX⇒XY=2(BC)=7cm
AC=12YZ⇒YZ=2(AC)=12cm
AB=12XZ⇒XZ=2(AB)=11cm
Perimeter of △xyz=7+12+11
=30cm
Hence (c).