In the given figure $A B ∥ C D, ∠ A P Q = 50^{\circ}$ and $∠ P R D = 120^{\circ}$ . Find $∠ Q P R$

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Solution

Interior opposite angles are same.
$∠ A P Q = ∠ P Q R = 50^{o}$
Exterior angle is sum of $2$ opposite interior angles
$∠ P R D = ∠ P Q R + ∠ Q P R$
$120 = 50 + ∠ Q P R$
$∠ Q P R = 70^{o}$ .

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Similar questions

In the given figure, AB||CD. If $∠ A P Q = 70^{\circ}$ and $∠ P R D = 120^{\circ}$ then $∠ Q P R = ?$

$(a) 50^{\circ}$

$(b) 60^{\circ}$

$(c) 40^{\circ}$

$(d) 35^{\circ}$

In the given figure, if AB || CD, ∠APQ = 50º and ∠PRD = 127º, find x and y.

A B | | C D, ∠ A P Q = 50^{\circ} a n d ∠ P R D = 127^{\circ}

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