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Question

In the given figure a block of mass M and density ρ is immersed in liquid of density σ. The block is attached to the spring from top and string from bottom. Elongation in the spring when string is tight is x and spring constant is Mg3x.

Column 1 Column 2 Column 3 (Tension developed in string) (Force generated in spring)(I)If ρ=2g/cc(i)T=4Mg3(P)F=Mg3 σ=1g/cc (II)If ρ=1g/cc(ii)T=Mg3(Q)F=0 σ=1g/cc (III)If ρ=1g/cc(iii)T=Mg2(R)F=Mg2 σ=2g/cc (IV)If ρ=1.2g/cc(iv)T=0(R)F=4Mg3 σ=0.8g/cc
Mark the incorrect combination.


A

(IV) (iv) (P)

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B

(I) (iv) (P)

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C

(III) (i) (P)

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D

(II) (ii) (P)

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Solution

The correct option is B

(I) (iv) (P)


ρ=2g/ccσ=1g/ccWapp=Mg(1σρ)=Mg2

Due to this elongation in spring is
kx=Mg2Mg3xx=Mg2x=3x2 T=0and F=Mg2
II. Wapp=0T=F=Mg3x.x=Mg3
III. x' = x
F=Mg3x.x=Mg3T=Mg3+Mg=43Mg

IV. Wapp=Mg(1σρ)
=Mg3F=Mg3
T = 0


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