In the given figure a block of mass M and density ρ is immersed in liquid of density σ. The block is attached to the spring from top and string from bottom. Elongation in the spring when string is tight is x and spring constant is Mg3x.
Column 1 Column 2 Column 3 (Tension developed in string) (Force generated in spring)(I)If ρ=2g/cc(i)T=4Mg3(P)F=Mg3 σ=1g/cc (II)If ρ=1g/cc(ii)T=Mg3(Q)F=0 σ=1g/cc (III)If ρ=1g/cc(iii)T=Mg2(R)F=Mg2 σ=2g/cc (IV)If ρ=1.2g/cc(iv)T=0(R)F=4Mg3 σ=0.8g/cc
Mark the incorrect combination.
(I) (iv) (P)
ρ=2g/ccσ=1g/ccWapp=Mg(1−σρ)=Mg2
Due to this elongation in spring is
kx′=Mg2Mg3xx′=Mg2x′=3x2∴ T=0and F=Mg2
II. Wapp=0T=F=Mg3x.x=Mg3
III. x' = x
∴ F=Mg3x.x=Mg3T=Mg3+Mg=43Mg
IV. Wapp=Mg(1−σρ)
=Mg3F=Mg3
T = 0