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Congruency of Triangles

In the given ...

Question

In the given figure, ∠A = ∠CED, prove that ∆CAB ∼ ∆CED. Also, find the value of x.

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Solution

Comparing ΔCAB and ΔCED,

∠CAB = ∠CED [Given]

∠ACB = ∠ECD [Common]

∴ ΔCAB ∼ ΔCED

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Similar questions

In Fig. 7.143, $∠ A = ∠ C E D$ , prove that $Δ C A B \sim Δ C E D$ . Also, find the value of x.

∠

∠

△

\sim

△

x

\frac{A D}{D C} = \frac{B E}{E C}

∠ C D E = ∠ C E D

△ C A B

A B ⊥ B C

D C ⊥ B C

D E ⊥ A C

△ C E D

\sim △ A B C .

In the figure given above, $∠ D C E = 20^{\circ}, ∠ E D C = 60^{\circ} .$ Find $∠ C E D .$

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