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Question
In the given figure a circle is inscribed in a â–³PQR with PQ=10cm,QR=8cm,PR=12cm.Length of PL is:
In the given figure a circle is inscribed in a â–³PQR with PQ=10cm,QR=8cm,PR=12cm.Length of PL is:
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Solution
The correct option is C 7 cm
From figure, we have,
1st side + 2nd side + 3rd side = perimeter of the triangle
x+(10−x)+x+(12−x)+(10−x)+(12−x)=10+12+8
10+12+10+12−2x=30
44−2x=30
⇒x=7
∴PL=x=7cm
From figure, we have,
1st side + 2nd side + 3rd side = perimeter of the triangle
x+(10−x)+x+(12−x)+(10−x)+(12−x)=10+12+8
10+12+10+12−2x=30
44−2x=30
⇒x=7
∴PL=x=7cm
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