In the given figure, a circle of radius 2m is inscribed in a right angled triangle of hypotenuse length 14 m, find the perimeter of the triangle?
A
17
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B
32
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C
16
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D
34
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Solution
The correct option is B
32
Let the circle touch the trinagle ABC at D, E and F. Let the length of AD be x Af =x (length of the tangents drawn from a point to the circle are equal in length). Similarly we can say DB =BE FC =EC DE =2 m (since perpendicular distance from the centre to the tangent is equal to radius) FC =14 -x (length of the hypotenuse is 14m) Perimeter of the triangle ABC =x+x+2+2+14-X+14-x =32 m.