In the given figure, a circle touches the side BC of ΔABC at P and AB and AC produced at Q and R respectively. If AQ = 15 cm, find the perimeter of ΔABC.
We know that
AQ = AR
AQ = AC + CR
But CR = CP
Therefore AQ = AC + CP …..(i)
Also AQ = AB + BQ
But BQ = BP
∴ AQ = AB + BP .….(ii)
Adding equations (i) and (ii)
2AQ = AC + CP + BP + AB
2AQ = Perimeter of ΔABC
Perimeter of ΔABC = 2 × 15 = 30 cm