In the given figure, a diode D is connected to an external resistance R=100Ω and an e.m.f. of 3.5V. If the barrier potential developed across the diode is 0.5V, the current in the circuit will be
A
35mA
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
30mA
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
40mA
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
20mA
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B30mA Net potential across the resistor is difference of the emf and the barrier potential. ∴iR=ε−Vbarrier=3.5−0.5=3 ⇒i=3100A=30×10−3A=30mA.