Question 91

In the given figure, a rectangle with perimeter 264 cm is divided into five congruent rectangles. Find the perimeter of one of the rectangles.

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Solution

Let l and b be the length and breadth of each rectangle, respectively.

Given, perimeter of a rectangle = 264 cm
According to the figure, 4l + 5b = 264 ......(i)
and 2l = 3b ......(ii)
Put the value of 2l from Eq.(ii) in Eq. (i), 2(2l) + 5b = 264
$\Rightarrow 2 \times 3 b + 5 b = 264 \Rightarrow 6 b + 5 b = 264 \Rightarrow 11 b = 264 \Rightarrow b = \frac{264}{11} \Rightarrow b = 24 c m ∴ l = \frac{3 b}{2} = \frac{3 \times 24}{2} = 36 c m$
Hence, perimeter of the rectangle = 2(l+b) = 2(36+24) = 120 cm

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Question 91 In the given figure, a rectangle with perimeter 264 cm is divided into five congruent rectangles. Find the perimeter of one of the rectangles.

Question 91

In the given figure, a rectangle with perimeter 264 cm is divided into five congruent rectangles. Find the perimeter of one of the rectangles.