In the given figure, a semicircle is drawn on the hypotenuse of the right-angled triangle. Another arc of radius 30 cm is drawn passing through A and C with O as the center. What is the area of the shaded region? (Take π as 3.14 and √3 = 1.732)
271.95 sq. cm
Area of the shaded region = Area of semicircle APC - Area of segment AQC
Area of semicircle = πr22=3.14×15×152=353.25 sq. cm
Area of segment = Area of sector OAQC - Area of triangle OAC
Consider triangle OAC
Since all sides are equal to 30 cm in the triangle, it is an equilateral triangle.
Area of an equilateral triangle = √34 × side2
=√34 × 302
= 225√3 sq.cm=389.7 sq. cm
Area of the sector OAQC = 60360×π×r2=16×3.14×30×30=471 sq. cm.
Hence, area of segment AQC = 471 - 389.7 = 81.3 sq. cm
Hence, area of the shaded region = Area of semicircle - area of segment AQC
= 353.25 - 81.3 = 271.95 sq. cm.