Question

In the given figure, a square is cut as shown in the first figure and rearranged to form a big square as shown in the second figure. Find the area of the big square in the second figure.

Answer 1

In the first figure, the square is of the side = 2cm + 6cm = 8cm

Area of the first square = $8\times 8=64sq.units$

It is cut and rearranged to get a bigger square as shown in the second figure with a square hole in the middle

The side of the square hole in the middle = 4cm

The area of the square hole in the middle = $4\times 4=16sq.units$

$\therefore$ The area of the bigger square = area of the 1st square + area of the square hole in the middle

$\therefore$ The area of the bigger square = 64 sq.units + 16 sq.units = 80 sq.units.

Note: The sq. units here refers to $c{m}^2$