In the given figure, a square OABC is inscribed in a quadrant OPBQ. If OA = 20 cm, find the area of the shaded region. [Use π = 3.14]

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Solution

In ΔOAB,

OB² = OA² + AB²

= (20)² + (20)²

Radius (r) of circle

Area of quadrant OPBQ

Area of OABC = (Side)² = (20)² = 400 cm²

Area of shaded region = Area of quadrant OPBQ − Area of OABC

= (628 − 400) cm²

= 228 cm²

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