In the given figure, $A B = A C$ and $A P = A Q$ . Prove that
$C P = B Q$

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Solution

In $△ A P C$ and $△ A Q B$
$A B = A C$ and $A P = A Q$
From the given figure, $∠ A = ∠ A$ [common in both the triangles
By using corresponding parts of congruent triangles concept we have
$B Q = C P$

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