Question

In the given figure, AB = AC and OB = OC. Prove that ∠ABO = ∠ACO.

Answer 1

Given: AB = AC
$\Rightarrow \angle B=\angle C$ ...(i)

$$\begin{gathered} \mathrm{Also},OB=OC \\ \Rightarrow \angle OBC=\angle OCB...\left(\mathrm{ii}\right) \end{gathered}$$

Subtracting (ii) from (i), we get:
$\angle B-\angle OBC=\angle C-\angle OCB$
∴ $\angle ABO=\angle ACO$
Hence, proved.