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Drawing Tangents to a Circle from a Point on the Circle

In the given ...

Question

In the given figure, AB and AC are tangents to the circle with centre O such that BAC = 40o. Then, BOC is equal to

40^o

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150^o

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50^o

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140^o

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Solution

The correct option is D
140^o

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Similar questions

∠ A P B = 50^{\circ}

∠

∠ A P B = 50^{\circ}

∠ O A B

∠ A P B = 50^{\circ}

∠

∠ A D C = 140^{\circ}, t h e n ∠ B A C

80^{\circ}

50^{\circ}

40^{\circ}

30^{\circ}

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