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Byju's Answer

Standard IX

Mathematics

Converse of Theorem 4

In the given ...

Question

In the given figure AB and CD are two chord of a circle having centre at O.Two perpendicular line OE and OF having equal lenghs are drawn as shown.If AB = 12 cm ,then the length of FD is equal to__.

6 cm

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12 cm

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18 cm

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24 cm

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Solution

The correct option is A 6 cm
In the given figure AB and CD are two chord and OE = OF

Hence, AB = CD
(Chords equidistant from the center of a circle are equal in length.)

So, AB = CD = 12 cm
Now, since the line from centre bisects the chord, CF = FD = $\frac{C D}{2}$

FD = $\frac{12}{2} = 6 c m$

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In the given figure AB and CD are two chord of a circle having centre at O.Two perpendicular line OE and OF having equal lenghs are drawn as shown.If AB = 12 cm ,then the length of FD is equal to__.

The correct option is A 6 cmIn the given figure AB and CD are two chord and OE = OF Hence, AB = CD (Chords equidistant from the center of a circle are equal in length.) So, AB = CD = 12 cm Now, since the line from centre bisects the chord, CF = FD = CD2 FD = 122=6 cm

The correct option is A 6 cm
In the given figure AB and CD are two chord and OE = OF

Hence, AB = CD
(Chords equidistant from the center of a circle are equal in length.)

So, AB = CD = 12 cm
Now, since the line from centre bisects the chord, CF = FD = $\frac{C D}{2}$

FD = $\frac{12}{2} = 6 c m$