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RHS Criteria for Congruency

In the given ...

Question

In the given figure; AB =BC and AD = EC. Prove that : BD = BE.

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Solution

In ΔABC,

AB = BC (given)

⇒ ∠BCA = ∠BAC (Angles opposite to equal sides are equal)

⇒ ∠BCD = ∠BAE ….(i)

Given, AD = EC

⇒ AD + DE = EC + DE (Adding DE on both sides)

⇒ AE = CD ….(ii)

Now, in triangles ABE and CBD,

AB = BC (given)

∠BAE = ∠BCD [From (i)]

AE = CD [From (ii)]

ΔABE ≅ ΔCBD

BE = BD (cpct)

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A D = A E

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In Fig. it is given that AB = BC and AD = EC. Prove that $Δ$ ABE $≅$ $Δ$ CBD
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Δ A D E

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