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Question

In the given figure, AB ⊥ BE and FE ⊥ BE. If BC = DE and AB = EF, then ΔABD is congruent to

(a) ΔEFC

(b) ΔECF

(c) ΔCEF

(d) ΔFEC

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Solution

It is given that

And

(Given)

(Given)

So (from above)

Hence

From (d).


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