In the given figure, AB||CD and BC||ED. Find the value of x.
BC ∥ ED and CD is the transversal.
Then,
∠BCD + ∠CDE = 180° Angles on the same side of a transversal line are supplementary
⇒ ∠BCD + 75 = 180
⇒ ∠BCD = 105°
AB ∥ CD and BC is the transversal.
∠ABC =∠BCD (alternate angles)
⇒ x = 105°