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Question

In the given figure, AB||CD and BC||ED. Find the value of x.

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Solution

BC ∥ ED and CD is the transversal.

Then,

∠BCD + ∠CDE = 180° Angles on the same side of a transversal line are supplementary

⇒ ∠BCD + 75 = 180

⇒ ∠BCD = 105°

AB ∥ CD and BC is the transversal.

∠ABC =∠BCD (alternate angles)

⇒ x = 105°


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