In the given figure- AB-CD and if - CFE - 90- then - FEB - -

As stated in question AB||CD and if ∠ CFE = 90^∘, so ∠ FEB is an alternate angle to ∠ CFE which should be equal. So, ∠ FEB = 90^∘. ...

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Angles and Types of Angles

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In the given figure, AB||CD and if $∠ C F E = 90^{\circ}$ , then $∠ F E B =$ __ $^{\circ}$ .

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